<PRE><B>Question 82586</B>
[x^3-x^2-10x/x^2-8x+16] + [-3x^2-6x+64/x^2-8x+16]

The denominators are the same so combine the numerators:

= [ x^3-4x^2-16x+64]/[(x-4)^2]

= [x^2(x-4)-16(x-4)]/[(x-4)^2]

= [(x-4)(x^2-16)]/[(x-4)^2

= [ (x-4)^2(x+4)]/[(x-4)^2]
Cancel the (x-5)^2 factors to get:

= x+4
==============
Cheers,
Stan H.
</PRE>