Question 968372
Let the length be x.
Let the breadth be y.
Perimeter=2(length+breadth)=2(x+y)
2(x+y)=72
x+y=36
y=36-x
Area=length*breadth
x(36-x)=288
36x-x^2=288
x^2-36x+288=0
*[invoke quadratic "x", 1, -36, 288 ]
x=24 m
y=12 m
The dimensions of the rectangle are 24m and 12m.