Question 968345
determine whether the point (-4,3) lies on the graph of x-2y=11
<pre>
The first coordinate -4 is the value for x.
The second coordinate 3 is the value for y.
[The coordinates are in alphabetical order, x first and y second.
That's a very important thing to know.]

Substitute (-4) for x and (3) for y in the equation and simplify.
If it comes out a true statement, then (-4,3) is a solution, and
it represents a point on the line. If it turns out false, it is 
not a solution, and does not represent a point on the line:

    x-2y = 11
(-4)-2(3)=11
     -4-6=11
      -10=11

That's clearly false, so (-4,3) does not lie on the graph of x-2y = 11.

Here is a graph of the line x-2y=11 and the point (-4,3)

{{{drawing(400,4000/19,-6,13,-7,5,

graph(400,4000/19,-6,13,-7,5),

line(-7,-9,14,1.5),

circle(-4,3,0.15),circle(-4,3,0.13),circle(-4,3,0.11),circle(-4,3,0.09),circle(-4,3,0.07),circle(-4,3,0.05),circle(-4,3,0.03),circle(-4,3,0.01),
locate(-4,3,"(-4,3)")
 )}}}

[Notice that there was a reason they gave you the point (-4,3).  
The reason they gave you that is because the point (3,-4) IS on 
the line, and students who get x and y backwards would think it 
was on the line, and get the problem wrong. 

Look what happens when you substitute x=3, and y=-4 instead:

     x-2y = 11
(3)-2(-4) = 11
      3+8 = 11
       11 = 11

That is true, so the point (3,-4) IS on the line as you can see below:

{{{drawing(400,4000/19,-6,13,-7,5,

graph(400,4000/19,-6,13,-7,5),

line(-7,-9,14,1.5),


circle(3,-4,0.15),circle(3,-4,0.13),circle(3,-4,0.11),circle(3,-4,0.09),circle(3,-4,0.07),circle(3,-4,0.05),circle(3,-4,0.03),circle(3,-4,0.01),




circle(-4,3,0.15),circle(-4,3,0.13),circle(-4,3,0.11),circle(-4,3,0.09),circle(-4,3,0.07),circle(-4,3,0.05),circle(-4,3,0.03),circle(-4,3,0.01),
locate(-4,3,"(-4,3)"),locate(3,-4,"(3,-4)")
 )}}}

But the point (-4,3) in NOT on the line.

Edwin</pre>