Question 967947
The given equation is in the slope-intercept form
The form is:
{{{ y = m*x + b }}} where
{{{ m }}} = slope
---------------------
{{{ y = (1/2)*x + 5 }}}
Any line which is perpendicular to this line will
have slope  =
{{{ m[1] = -1/m }}}
{{{ m[1] = -1/((1/2)) }}}
{{{ m[1] = -2 }}}
----------------
Now I can use the general point-slope formula:
{{{ ( y - 5 ) / ( x -(-2) ) = -2 }}}
{{{ ( y - 5 ) / ( x + 2 ) = -2 }}}
{{{ y - 5 = -2*( x + 2 ) }}}
{{{ y - 5 = -2x - 4 }}}
{{{ y = -2x + 1 }}}
--------------------
check:
slope = {{{ -2 }}} 
OK
Does it go through ( -2, 5 ) ?
{{{ y = -2x + 1 }}}
{{{ 5 = -2*(-2) + 1 }}} 
{{{ 5 = 4 + 1 }}}
{{{ 5 = 5 }}}
OK