Question 967933

If {{{f(x) = 2x + 1}}} and {{{g(x) = x^2}}}, then:


{{{(f o g )(x) = f( g(x)) }}}

{{{(f o g )(x) =2x^2 + 1 }}}


{{{(g o f )(x) = g( f(x)) }}}

{{{(g o f )(x) =   (2x + 1)^2 }}}

{{{(g o f )(x) =  4x^2 + 4x+1}}}