Question 967790
your equation is x^2 + 2x + 1 > 0


if you set your equation to y, then the equation becomes:


y = x^2 + 2x + 1


if x^2 + 2x + 1 > 0, then y > 0 as well because y = x^2 + 2x + 1.


you would graph y = x^2 + 2x + 1.


you would look for all values of y that are > 0.


the graph of your equation looks like this:


{{{graph(400,400,-10,10,-10,10,x^2 + 2x + 1)}}}


your graph touches the x-axis at x = -1.


that means that y = 0 when x = -1.


the solution to x^2 + 2x + 1 > 0 is all values of x except at x = -1.


this means that y > 0 at all values of x except at x = -1, because y = x^2 + 2x + 1.