<PRE><B>Question 967724</B>
Two cylindrical containers are shown. Container A has a radius r and a height of h and holds a maximum of 100 ounces of water. Container B has a radius of 4r and a height of 12 h .


formula for volume of container A is v1 = pi * r^2 * h.


formula for volume of container B is v2 = pi * (4r)^2 * 12h.


simplify formula for container B to get v2 = pi * 16 * r^2 * 12 * h.


simplify further to get v2 = 192 * pi * r^2 * h.


you have v1 = pi * r^2 * h.
you have v2 = 192 * pi * r^2 * h.


the volume for container B is 192 times the volume for container A.


if container A holds 100 ounces of water, then container B should contain 192 * 100 ounces of water which would then be equal to 19,200 ounces of water.


this assumes the ratio of ounces to volume remains the wame.


100 / v1 = x / (192 * v1)


cross multiply to get 100 * 192 * v1 = x * v1


divide both sides of that equation by v1 to get 100 * 192 = x.


solve for x to get x= 19,200 ounces.


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