Question 967714

 the point-slope form to find the equation of the line:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

if given
 
point ({{{-12}}},{{{ 2}}}) and    {{{m =-1/3}}}, then we have

{{{2=-(1/3)(-12)+b}}}...solve for {{{b}}}

{{{2=(1/cross(3)1)(cross(12)4)+b}}}

{{{2=4+b}}}

{{{2-4=b}}}

{{{b=-2}}}

so, your equation is {{{y=-(1/3)x-2}}}

{{{drawing( 600, 600, -15, 10, -10, 10,circle(-12,2,.12),locate(-12,2,p(-12,2)), graph( 600, 600, -15, 10, -10, 10, -(1/3)x-2)) }}}