Question 967683
to find out what are the {{{x}}},{{{y}}} intercepts for this line, first use given points to find equation of a line

({{{-4}}},{{{5}}})

{{{y=mx+b}}}
{{{5=m(-4)+b}}}
{{{5=-4m+b}}}........eq.1
solve eq.1 for {{{b}}}
{{{5=-4m+b}}}
{{{5+4m=b}}}

({{{8}}},{{{-7}}})

{{{y=mx+b}}}
{{{-7=m(8)+b}}}
{{{-7=8m+b}}}.....eq.2

substitute {{{b}}}

{{{-7=8m+b}}}

{{{-7=8m+5+4m}}}

{{{-7-5=12m}}}

{{{-12=12m}}}

{{{-12/12=m}}}

{{{-1=m}}}....go to {{{5+4m=b}}} and find {{{b}}}

{{{5+4(-1)=b}}}
{{{5-4=b}}}
{{{1=b}}}

so, the equation of your line is {{{y=-x+1}}}

 since y-intercept occurs where {{{x=0}}}, so it is at {{{y=1}}}

x-intercept occurs where {{{y=0}}}, so it is at {{{0=-x+1}}}=>{{{x=1}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(8,-7,.12),circle(-4,5,.12),locate(8,-7,p(8,-7)),locate(-4,5,p(-4,5)),
 graph( 600, 600, -10, 10, -10, 10, -x+1)) }}}