Question 82549
{{{x-5/x=4}}}
Get the 5/x term alone on one side of the equation:
{{{-5/x=4-x}}}
multiply each side of the equation by x to get that x out of the denominator:
{{{-5=4x-x^2}}}
Put the quadratic in standard for - i.e. equate to zero:
{{{x^2-4x-5=0}}}
Factor:
{{{(x-5)(x+1)=0}}}
Equate each term to zero and solve for x:
{{{highlight(x=5)}}}
{{{highlight(x=-1)}}}
Good Luck,
tutor_paul@yahoo.com