Question 967449
given that tan 0 = -1/6 and 0 is in the fourth quadrant m, determine cos 0 round your answer to three decimal places
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hypotenuse of reference right triangle in quadrant IV =&#8730;(6^2+1^2)=&#8730;37
cos 0=6/&#8730;37=(6&#8730;37)/37&#8776;0.986