<PRE><B>Question 967608</B>
At this point, you need to divide 1800 lb into oats and soy meal. So, let us assume that farmer adds x lb of oats. Then, the added soy meal will be 1800-x lb.
Total protein content obtained will be (x*0.118)+ ((1800-x)*0.445) which needs to be equal to the 265.80 lb that you calculated.

Therefore,

(x*0.118)+((1800-x)*0.445) = 265.80 
1800* 0.445 - 265.80 = x*(0.445-0.118)
535.2 = x*0.327
Hence x = amount of oats added = 1636.69 lb
amount of soy meal = 1800-x = 163.20

CHECK:

total protein required = 0.14*2400 = 336
total protein added = 600*0.117 + 1636.69*0.118 + 163.20*0.445 = 70.2+193.13+72.624 = 335.954 

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