Question 967561

an equation for the line parallel to the line {{{-25x + 5y = 4}}} through the point ({{{-8}}}, {{{-7}}}):

{{{-25x + 5y = 4}}}. ..first write it in slope-intercept form to find a slope

{{{ 5y = 25x +4}}}

{{{ y = 25x/5 +4/5}}}

{{{ y = highlight(5)x +4/5}}}....as you can see, the slope is {{{m=5}}}, and we know that the line parallel to this line will have same slope

 so far the equation of the parallel  line is:

{{{y=5x+b}}}...we will use given point ({{{-8}}}, {{{-7}}}) to find y-intercept {{{b}}}

{{{-7=5(-8)+b}}}

{{{-7=-40+b}}}

{{{-7+40=b}}}

{{{b=33}}}

so,the equation is {{{y=5x+33}}}


{{{drawing( 600, 600, -10, 10, -10, 50,
circle(-8,-7,.12),locate(-8,-7,p(-8,-7)),
 graph( 600, 600, -10, 10, -10, 50, 5x +4/5,5x+33)) }}}