Question 967546
Evaluate: sin π/2 - cos 3π/4 - tan π/6 
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sin(pi/2) = 1
cos(3pi/4) = -sqrt(2)/2)
tan(pi/6) = sqrt(3)/3
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Ans:: 1 - sqrt(2)/2 - sqrt(3)/3
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= [6 - 3sqrt(2) - 2sqrt(3)]/6
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Cheers,
Stan H.
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