Question 967393
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. 
2 sin 2θ − 3 sin θ = 0 
2(2sinxcosx)-3sinx=0
4sinxcosx-3sinx=0
sinx(4cosx-3)=0
sinx=0+πk, π+πk, k=any integer
or
4cosx-3=0
cosx=3/4
x=0.732+2πk, 5.551+2πk, k=any integer