Question 967422
Strain A


{{{1.1=1*e^(k*8)}}}
{{{ln(1.1)=ln(1)+k*8*ln(e)}}}'
{{{ln(1.1)=8k}}}
{{{k=ln(1.1)/8}}}
{{{highlight(k[a]=0.0119)}}}


Strain B


{{{1.12=1*e^(k*9)}}}
{{{ln(1.12)=0+k*9}}}
{{{k=ln(1.12)/9}}}
{{{highlight(k[b]=0.0126)}}}


Strain B  grows faster than strain A.