Question 967188
{{{dy/dx=(d/dx)(4x^4+10)}}}


{{{dy/dx=16x^3+0}}}


At x=2,
{{{dy/dx=16*(2)^3=16*8=highlight_green(128)}}}, the slope of the tangent line at x=2.


The y coordinate for x=2, according to the given degree-four equation is {{{4*(2)^4+10=highlight_green(74)}}}.


You want the equation of the tangent line at point (2,74) and slope 128.  You can use point-slope form to continue...
{{{highlight_green(y-74=128(x-2))}}}.....