Question 967145
you have

{{{10(y+3)^2-(x-4)^2=80 }}}

and you want to obtain:

{{{(x - h)^2/a^2 - (y - k)^2/b^2 = 1}}}


both sides divide by {{{80}}}


{{{10(y+3)^2/80-(x-4)^2/80=80/80 }}}


{{{cross(10)(y+3)^2/cross(80)8-(x-4)^2/80-1 }}}


{{{(y+3)^2/8-(x-4)^2/80=1 }}}


{{{ graph( 600, 600, -10, 10, -10, 10,sqrt(8((x-4)^2/80+1))-3,-sqrt(8((x-4)^2/80+1))-3 ,sqrt(8((x-4)^2/80+1))-3) }}}