Question 966979
The rational root of the equation 2x^3-x^2-4x+2=0 is
we can group factor here
rearrange
2x^3 - 4x - x^2 + 2 = 0
factor out 2x and -1
2x(x^2 - 2) - 1(x^2 - 2) = 0
Factor out (x^2-2)
(x^2 - 2)(2x - 1) = 0
Three solutions
x^2 = 2
x = +{{{sqrt(2)}}}
x = -{{{sqrt(2)}}}
and
2x = 1
x = 1/2