Question 967084

{{{pi/12=15}}}°

 {{{sin(pi/12)* cos(pi/12 )}}}

={{{sin(15)* cos(15 )}}}

={{{((sqrt(3)-1)/(2 sqrt(2)))*((sqrt(3)+1)/(2 sqrt(2)))}}}

={{{((sqrt(3))^2-1)/(2sqrt(2)*2sqrt(2))}}}

={{{(3-1)/(4*2)}}}

={{{cross(2)/(4*cross(2))}}}

={{{1/4}}}