Question 967086
Alexa drew a rectangle with an area of 36 square centimeters. The rectangle she drew has the smallest perimeter possible for this area. What is the length and width of the rectangle she drew?
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Area:: L*W = 36 cm^2
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Perimeter:: P = 2L + 2W
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Equation::
P = 2(36/W) + 2W
P = (72/W) + 2W
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Find the minimum "P"::
P' = -72/W^2 + 2
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Solve:: -72/W^2 + 2 = 0
-72/W^2 = -2
W^2 = 36
W = 6 cm (Width)
Length = 36/6 = 6 cm 
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Cheers,
Stan H.
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