Question 967004
1.{{{B=2(R+G)}}}
2.{{{3R+2G=2B}}}
3.{{{B+G+R=22}}}
Substituting from eq. 1 into eq. 2,
{{{3R+2G=4(R+G)}}}
{{{3R+2G=4R+4G}}}
{{{R+2G=0}}}
There's a problem here.
From this equation, one value is positive and the other is negative. 
Can't have a negative number of reds, greens, or blues.
Please re-check the problem set up and repost.