Question 966877
{{{y=2^x}}}
Interchange x and y and solve for y.
This new y is the inverse.
{{{x=2^y}}}
{{{y=log(2,(x))}}}
{{{f^(-1)(x)=log(2,(x))=log((x)))/log((2))}}}
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Domain of {{{f(x)}}} : ({{{-infinity}}},{{{infinity}}})
Range of {{{f(x)}}}: ({{{0}}},{{{infinity}}})
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Domain of {{{f^(-1)(x)}}} : ({{{0}}},{{{infinity}}})
Range of {{{f^(-1)(x)}}}: ({{{-infinity}}},{{{infinity}}})
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