Question 966956
From the second equation,
{{{y=5-4x}}}
Substituting into the first,
{{{5-4x=x^2-2x-19}}}
{{{x^2+2x-24=0}}}
{{{(x+6)(x-4)=0}}}
So the second solution is,
{{{x-4=0}}}
{{{x=4}}}
Then,
{{{y+4(4)=5}}}
{{{y=-11}}}
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