Question 966710
An airplane is headed northeast, bearing 45◦, with an air speed of 500 miles per hour, with a wind blowing with
bearing 315◦, at a speed of 75 miles per hour. Find the ground speed (to nearest tenth of a mph) and the actual course of the plane (to nearest tenth of a degree).
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It's a direct crosswind --> a right triangle.
The groundspeed is the hypotenuse.
{{{GS = (500^2 + 75^2) = sqrt(255625)}}}
GS =~ 505.6 mi/hr
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The angle between the heading and the ground track's tangent = 75/500
Angle =~ 8.53 degs
Add that to 045 --> ground track of 53.5 degs
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PS  Planes don't use fractions of mi/hr (they use knots) or of degrees.