Question 966439

if {{{m=-1/2}}} and {{{b=-2}}}, then your line in slope intercept form is {{{y=-(1/2)x-2}}}

since you already have one point, y-intercept ({{{0}}},{{{-2}}}), find one mor point and graph a line

{{{x}}}{{{y}}}

{{{-4}}}{{{0}}}.......{{{0=-(1/2)x-2}}}=>{{{(1/2)x=-2}}}=>{{{x=-4}}}


{{{drawing( 600,600, -10, 10, -10, 10,
circle(0,-2,.12),circle(-4,0,.12),
locate(0,-2,p(0,-2)),locate(-4,0.7,p(-4,0)),
 graph( 600,600, -10, 10, -10, 10,-(1/2)x-2)) }}}