Question 82365
{{{((x^7y^-4z^0)/(5^-2x^3y^-8z^-9))^2}}}
:
Any number with a 0 exponent is 1, so we have:
{{{((x^7y^-4)/(5^-2x^3y^-8z^-9))^2}}}
:
Combine like terms in the numerator, follow the rules of exponents:
{{{(5^2x^((7-3))y^((-4+8))z^9)^2}}}
:
{{{(25x^4y^4z^9)^2}}}
:
Square each term:
{{{625*x^8y^8z^18}}}
:
I have confidence in the method, however, a lot of chance for error here.
I advise you to do it yourself to confirm my solution