Question 966223

{{{log (2x) - log(9) = 1 }}}

{{{log(2)+log(x)-log(9) = 1 }}}.......since {{{log(10) = 1}}}, we have

{{{log((x)) = log(10)+log(9)-log(2) }}}

{{{log((x)) = log((10*9)/2) }}}

{{{log((x)) = log((5*9)) }}}

{{{log((x)) = log((45)) }}}

{{{x = 45 }}}