Question 966123
.
Let:
N=first integer; N+2=second integer
{{{N(N+2)=168}}} Subtract 168 from each side.
{{{N^2+2N-168=0}}}
{{{(N-12)(N+14)=0}}}
{{{N-12=0}}} {{{or}}} {{{N+14=0}}}
{{{N=12}}} {{{or}}} {{{N=-14}}}
ANSWER 1: The first positive integer is 12.
.
N+2=12+2=14
ANSWER 2: The second integer is 14
.
CHECK:
Product=168
{{{(12)(14)=168}}}
{{{168=168}}}