Question 966065
x = amount put into the 10% account
y = amount put into the 12% account


" there is $400 more in the account that pays 12% than there is in the other account" so {{{y = x+400}}}


"The two accounts pay 10% and 12% in annual interest" and "the total interest for a year is $136" so we know {{{0.10x+0.12y = 136}}}


Multiply everything by 100 to get {{{10x+12y = 13600}}}


and then plug in {{{y = x+400}}} and solve for x


{{{10x+12y = 13600}}}


{{{10x+12(x+400) = 13600}}} replace y with x+400


{{{10x+12x+4800 = 13600}}}


{{{22x+4800 = 13600}}}


{{{22x+4800-4800 = 13600-4800}}} Subtract 4800 from both sides.


{{{22x+0 = 8800}}}


{{{22x = 8800}}}


{{{22x/22 = 8800/22}}} Divide both sides by 22.


{{{x = 400}}}


Now use this to find y. Plug it into {{{y=x+400}}}


{{{y=x+400}}}


{{{y=400+400}}} replace x with 400


{{{y=800}}}


So $400 was put into the 10% account while $800 was put into the 12% account.


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