Question 966041
In the morning, Maria drove to her business appointment at 70 mph. Because of higher traffic in the afternoon, her average speed on the return trip was 60 mph. This made the return trip take 1/4 hr longer. How far away was the appointment?
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let x=distance to appointment
travel time=distance/speed
x/60-x/70=1/4
4x/60-4x/70=1
lcd:60*70=4200
280x-240x=4200
40x=4200
x=105
How far away was the appointment? 105 mi