Question 965984
P(C)= 0.2 
P(B)= 0.3
P(C') = 1-P(C)= 0.8
P(B intersection C')= P(B)*P(C') 
                    =0.3*0.8
                    = 0.24
P(BuC')= P(B)+P(C')-P(B intersection C')
       = 0.3+0.8-0.24
        =0.86
P(BuC')'=1 -P(BuC')
        =1-0.86
        =0.14