Question 965888
{{{f(x)=d(x-1)^2+18}}}
So then to find P and T,
{{{d(x-1)^2+18=0}}}
{{{d(x-1)^2=-18}}}
{{{(x-1)^2=-18/d}}}
{{{x-1=0 +- sqrt(-18/d)}}}
{{{x=1 +- sqrt(-18/d)}}}
Also you can find T.
{{{-2x+8=0}}}
{{{2x=8}}}
{{{x=4}}}
So then you can find T.
{{{1+sqrt(-18/d)=4}}}
{{{sqrt(-18/d)=3}}}
{{{-18/d=9}}}
{{{d=-2}}}
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{{{f(x)=-2(x-1)^2+18}}}
{{{f(x)=-2(x^2-2x+1)+18}}}
{{{f(x)=-2x^2+4x-2+18}}}
{{{f(x)= -2x^2+4x+16 }}}
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