Question 965693
Let the three consecutive odd integers be (x-2),x and (x+2) respectively.
We have (x-2)(x+2)=2x-1
x^2-4=2x-1
x^2-2x-3=0
x^2-3x+x-3=0
x(x-3)+1(x-3)=0
(x+1)(x-3)=0
x=3
The consecutive odd integers are 1,3 and 5 respectively.