Question 965470
the salary of A is 20% below the salary of B and the salary of C is 56.25% greater than the salary of A.


by how much % is the salary of B less than the salary of C?


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salary of A is .8 * B.


this is because 20% less than salary of B is equal to B - .20 * B which is equal to (1 - .2) * B which is equal to .8 * B.


salary of C is 1.5625 * salary of A.


this is because 56.25% greater than A is equal to A + .5625 * A which is equal to (1 + .5625) * A which is equal to 1.5625 * A.


so you have:


A = .8 * B
C = 1.5625 * A.


in the equation of A = .8 * B, solve for B to get B = A / .8 which is the same as 1/.8 * A which simplifies to B = 1.25 * A.   


you now have:


A = .8 * B
B = 1.25 * A
C = 1.5625 * A.


you want to know what percent the salary of B is less than C.


the formula for this would be:


(C - B) / C * 100%


since B = 1.25 * A and C = 1.5625 * A, this formula becomes:


(C - B) / C * 100% = [(1.5625 * A - 1.25 * A) / (1.5625 * A)] * 100%


The A in the denominator and the A in the numerator cancel out and you are left with:


(C - B) / C * 100% = [(1.5625 - 1.25) / 1.5625] * 100%.


sinplify this to get (C - B) / C * 100% = 20%.


that's your solution.


B is 20% less than C.


to see if you're correct, give some values to A and B and C and see if this makes sense.


let B = 1000
this means that A is equal to 800 because A is equal to 80% of B.
this means that C is equal to 1250 because 80% of 1250 is equal to 1000.


if the numbers are correct, than C must be 56.25% greater than A.


800 * 1.5625 is equal to 1250.


the numbers check out so the solution appears to be good.


i'd go with it.


solution is that B is 20% less than C.