Question 965388
Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
{{{2cos^2(x)-3sinx-3=0}}}
{{{2(1-sin^2(x)-3sinx-3=0}}}
{{{2-2sin^2(x)-3sinx-3=0}}}
{{{-2sin^2(x)-3sinx-1=0}}}
{{{2sin^2(x)+3sinx+1=0}}}
(2sinx+1)(sinx+1)=0
sinx=-1/2
no solution, not in domain
or
sinx=-1
no solution, not in domain