Question 965436
.
x and y are the integers
x=2y+1
xy=105 Substitute for x
(2y+1)(y)=105 Subtract 105 from each side
2y^2+y-105=0*[invoke quadratic "y", 2, 1, -105 ]
y=7 ANSWER 1: One of the integers is 7
x=2y+1=2(7)+1=14+1=15 ANSWER 2: The other integer is 15