Question 965424
Use the given conditions to write an equation for each line in point-slope form. 
Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6.
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point-slope form of equation: (y1-y2)=m(x1-x2), m=slope
given equation: (1/5)x+6
slope=1/5
slope of perpendicular line=-5 (negative reciprocal)
equation of perpendicular line: 
y-(-3)=-5(x-2)
y+3=-5x+10