Question 965417
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{{{x^2+(x+3)^2=45}}}
{{{x^2+x^2+6x+9=45)}}} Subtract 45 from each side.
{{{2x^2+6x-36=0}}} Divide by 2
{{{x^2+3x-18=0}}}
{{{(x+6)(x-3)=0}}}
{{{x+6=0}}} {{{or}}} {{{x-3=0}}}
{{{x=-6}}} {{{or}}} {{{x=3}}}
ANSWER: The positive number is 3.
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CHECK:
{{{x^2+(x+3)^2=45}}}
{{{3^2+(3+3)^2=45}}}
{{{9+6^2=45}}}
{{{9+36=45}}}
{{{45=45}}}