Question 965380
log6(7x-2)=1+log6(x+5)
:
subtract log6(x+5) from both sides
log6(7x-2) - log6(x+5) = 1
:
subtraction means divide in logs
{{{log(6,((7x-2)/(x+5))) = 1}}}
:
the exponent equiv
{{{(7x-2)/(x+5) = 6^1}}}
or just
{{{(7x-2)/(x+5) = 6}}}
:
multiply both sides by (x+5)
7x - 2 = 6(x + 5)
7x - 2 = 6x + 30
7x - 6x = 30 + 2
x = 32