Question 965206
{{{y=2x^2+8x+5}}}
{{{y=2(x^2+4x)+5}}}
{{{y=2(x^2+4x+4)+5-2(4)}}}
{{{y=2(x+2)^2-3}}}
The vertex (turning point) is (-2,-3).
Since {{{2>0}}}, the parabola opens upwards so the value at the vertex is a minimum.
*[illustration aws.JPG].