Question 965140
lateral area/4=area of one side =1/2(base edge)(slant height)
{{{2400in^2/4=(1/2)bs}}}
{{{600in^2=(1/2)(48in)(s)}}}
{{{600in^2=(24in)s}}}
{{{25in=s}}} The slant height is 25 inches.
The height and 1/2 the base length form a right triangle with the slant height as hypotenuse, so:
{{{s^2=(b/2)^2+h^2}}} where h is the height
{{{(25in)^2=(24in)^2+h^2}}}
{{{(25in)^2-(24in)^2=h^2}}}
{{{sqrt((625in^2)-(576in^2))=h}}}
{{{sqrt(49in^2)=h}}}
{{{7in=h}}} ANSWER: The height of the pyramid is 7 inches.