Question 965068
Let {{{ t }}} = time in hours for 1st trip
{{{ 9 - t }}} = time in hours for 2nd trip
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{{{ 156 / ( 9 - t ) = 294 / t + 3 }}}
Multiply both sides by {{{ t*( 9 - t ) }}}
{{{ 156t = 294*( 9 - t ) + 3*t*( 9 - t ) }}}
{{{ 156t = 2646 - 294t + 27t - 3t^2 }}}
{{{ 3t^2 + 423t - 2646  = 0 }}}
{{{ t^2 + 141t - 882 = 0 }}}
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Use quadratic formula:
{{{ t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{ a = 1 }}}
{{{ b = 141 }}}
{{{ c = -882 }}}
First find {{{ t }}}
Find {{{ 294/t }}}
Then find
{{{ 156 / ( 9-t ) }}}