Question 964991

I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2).
<pre>y is 0 on the x-axis, so ({{{2 - 2 * sqrt(2)}}}{{{","}}}{{{0}}}) and ({{{2 + 2 * sqrt(2)}}}{{{","}}}{{{0}}}) are the x-intercepts
x is 0 on the y-axis, so ({{{0}}}{{{"'"}}}{{{- 2}}}) is the y-intercept
You've already determined the coordinates of the vertex, so you have what's needed to form the equation of the parabola