Question 965005
a) ^p = 42 / 140 = 0.30
b) P = .45 and Q = .55, then
The mean = P = .45
Standard Deviation = sqrt(PQ/n) = sqrt((.45*.55) / 140) = 0.042045893 approx 0.04
c) z-score = (X - mean) / std dev = (0.472 - 0.45) / 0.04 = 0.55
consult the z-tables for the probability associated with z-score = 0.55
The probability (X < 0.472) = 0.7088 approx .71
now we want the probability (X > 0.472) which is equal to
1 - 0.71 = 0.29