Question 965022
Perpendicular lines have slopes that are negative reciprocals.
{{{7y=-6x+4}}}
{{{y=-(6/7)x+4/7}}}
So,
{{{m[p]*(-(6/7))=-1}}}
{{{m[p]=7/6}}}
Use the point-slope form,
{{{y-(-7)=(7/6)(x-5)}}}
{{{y+7=(7/6)(x-5)}}}
{{{6y+42=7x-35}}]
{{{-7x+6y=-77}}}
{{{highlight(7x-6y=77)}}}