Question 964915
Find the derivative. 
The value of the derivative at a point is the slope of the tangent line at that point.
{{{df/dx=2x+1}}}
{{{df/dx=2(2)+1}}}
{{{df/dx=4+1}}}
{{{m=df/dx=5}}}

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{{{4y^3dy-8ydy=4x^3dx-18xdx}}}
{{{(4y^3-8y)dy=(4x^3-18x)dx}}}
{{{dy/dx=(4x^3-18x)/(4y^3-8y)}}}
{{{dy/dx=(2x^3-9x)/(2y^3-4y)}}}
{{{dy/dx=(2(3)^3-9(3))/(2(2)^3-4(2))}}}
{{{dy/dx=(2(27)-27)/(2(8)-8)}}}
{{{m=dy/dx=(27)/(8)}}}