Question 964790
Prove that:

secx/sinx - sinx/cosx = cotx is an identity.
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secx/sinx - sinx/cosx = cotx
secx/sinx - sinx/cosx = cos/sin
1/sin*cos - sin/cos = cos/sin
Multiply by sin*cos
1 - sin^2 = cos^2
1 = sin^2 + cos^2 (Pythagorean Identity)
QED
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If anyone can post an example where working on one side only makes a difference, I would like to see it.