Question 964455
{{{A+B=26}}}
{{{A=(3/10)B}}}
Substituting,
{{{(3/10)B+(10/10)B=26}}}
{{{(13/10)B=26}}}
{{{B=260/13}}}
{{{B=20}}}
Then,
{{{A=(3/10)(20)}}}
{{{A=6}}}