Question 964703
We are given length(l) = 4*sqrt(2) and width(w) = 3*sqrt(2)
8) Perimeter(P) = 2l +2w
P = 2*(4*sqrt(2)) +2*(3*sqrt(2))
P = 8*sqrt(2) + 6*sqrt(2)
P = 14*sqrt(2) feet
9) Area(A) = (4*sqrt(2)) * (3*sqrt(2))
A = 12*sqrt(2)^2
A = 12 * 2 = 24 square feet
10) diagonal(d)^2 = (4*sqrt(2))^2 + (3*sqrt(2))^2
d^2 = 32 + 18 = 50
d = sqrt(50) = 5*sqrt(2) feet